Code As Trees

int main() {

   char c;
   int i;
   int even;
   i=0;
   even=0;
   while (i < 10) {
     i = i+1;
     if (i == (i/2)*2) {
       even = even +1;
     }
   }
   i = even + 23;

}

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EditHint: Unfinished? Explanation requested.

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See also: AbstractSyntaxTree.